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Sayantan Sen

@sayantansen

Postdoc @quantumlah @NUSingapore Previously: Postdoc @NUSComputing https://sites.google.com/view/sayantans

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Latest posts by Sayantan Sen @sayantansen

QCOW Department of Computer Science - People: Sergii Strelchuk - QCOW

The 2nd Quantum Cambridge–Oxford–Warwick (QCOW) Workshop will take place at Warwick on April 23–24. Theme: Quantum Learning Theory. The programme will feature tutorials and accessible in-depth talks on recent advances by leading experts. Speakers/updates:
qcow.cs.ox.ac.uk/

22.02.2026 13:15 👍 15 🔁 4 💬 0 📌 0
Preview
Pseudo-deterministic Quantum Algorithms We initiate a systematic study of pseudo-deterministic quantum algorithms. These are quantum algorithms that, for any input, output a canonical solution with high probability. Focusing on the query co...

This new preprint by Hugo Aaronson, Tom Gur, and Jiawei Li on quantum pseudodeterministic* algorithms, a line of research hitherto unexplored, seems quite interesting! cc/ @tomgur.bsky.social @jiaweili.bsky.social

arxiv.org/abs/2602.17647

*must consistently output a canonical solution w.h.p.

20.02.2026 04:18 👍 10 🔁 1 💬 1 📌 0
We want to evaluate
$$
\sum_{\color{red}k=0}^\infty (\color{red}k+1) \color{blue}p^{\color{red}k}\,.
$$
Introduce the function $f$, for $|\color{blue}x|<1$:
$$
f(\color{blue}x) = \sum_{\color{red}k=0}^\infty \color{blue}x^{\color{red}k}\,.
$$
That's a nice geometric series, and we easily get $f(\color{blue}x) = \frac{1}{1-\color{blue}x}$. So we can differentiate that:
$$
f'(\color{blue}x) = \frac{1}{(1-\color{blue}x)^2} 
$$
But $f$ was defined as a power series, and we can also differentiate *that* termwise:
$$
f'(\color{blue}x) = \sum_{\color{red}k=1}^\infty \color{red}k \color{blue}x^{\color{red}{k-1}} = \sum_{\color{red}k=0}^\infty {(\color{red}k+1)} \color{blue}x^{\color{red}{k}}\,.
$$
Well, $f'(\color{blue}x)= f'(\color{blue}x)$ (!), so we can use both expressions, and evaluate them at $\color{blue}p$:
$$
\boxed{\sum_{\color{red}k=0}^\infty {(\color{red}k+1)} \color{blue}p^{\color{red}{k}}
= \frac{1}{(1-\color{blue}p)^2}}
$$

We want to evaluate $$ \sum_{\color{red}k=0}^\infty (\color{red}k+1) \color{blue}p^{\color{red}k}\,. $$ Introduce the function $f$, for $|\color{blue}x|<1$: $$ f(\color{blue}x) = \sum_{\color{red}k=0}^\infty \color{blue}x^{\color{red}k}\,. $$ That's a nice geometric series, and we easily get $f(\color{blue}x) = \frac{1}{1-\color{blue}x}$. So we can differentiate that: $$ f'(\color{blue}x) = \frac{1}{(1-\color{blue}x)^2} $$ But $f$ was defined as a power series, and we can also differentiate *that* termwise: $$ f'(\color{blue}x) = \sum_{\color{red}k=1}^\infty \color{red}k \color{blue}x^{\color{red}{k-1}} = \sum_{\color{red}k=0}^\infty {(\color{red}k+1)} \color{blue}x^{\color{red}{k}}\,. $$ Well, $f'(\color{blue}x)= f'(\color{blue}x)$ (!), so we can use both expressions, and evaluate them at $\color{blue}p$: $$ \boxed{\sum_{\color{red}k=0}^\infty {(\color{red}k+1)} \color{blue}p^{\color{red}{k}} = \frac{1}{(1-\color{blue}p)^2}} $$

Let's say you want, e.g., to compute the expectation of a Geometric r.v. That'll involve, at some point, evaluating a series of the form "Σ (k+1) p^k" which looks like what Lovecraft may have done to a geometric series. How to do it?

One trick I enjoy: differentiate the same function, in two ways!

18.02.2026 12:27 👍 38 🔁 6 💬 1 📌 0

A bit, typically encoded as 0 or 1, is a binary value encoding a unit of information. A qubit is the quantum analogue, encoding a unit of quantum information.

Introducing the hobit, encoding a unit of fantastic information!

17.02.2026 06:06 👍 35 🔁 2 💬 2 📌 1
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3rd "Mathematics of Data" Summer School is being held in Singapore in June. Applications for attendance (with accommodation for most & no registration fee for all) are open throughout February and possibly longer: ims.nus.edu.sg/events/ma_da...

04.02.2026 06:45 👍 6 🔁 6 💬 0 📌 1
ECCC - TR26-009

New short note up! In which I attempt to explain something which took me a good ten years to understand: a lower bound method for symmetric properties of distributions, or "how to use univariate polynomials to build your hard instances"

Comments welcome!

📝 eccc.weizmann.ac.il/report/2026/...

27.01.2026 11:03 👍 17 🔁 2 💬 1 📌 0
Screenshot of the YouTube playlist for the course.

Screenshot of the YouTube playlist for the course.

On the topic of online resources, worth spreading the word again about Ryan O'Donnell's "CS Theory Toolkit" course: "Covers a large number of the math/CS topics that you need to know for reading and doing research in Computer Science Theory"
youtube.com/playlist?lis... @booleananalysis.bsky.social

26.01.2026 03:55 👍 31 🔁 8 💬 1 📌 0

An exciting graduate summer school at NUS on "Mathematical Aspects of Data Science" on June 22—July 1, organized by Daniel Bartl, Shahar Mendelson, Jonathan Scarlett , and Roman Vershynin.

Free registration, (some) free accommodation. Apply by ⏰ Feb 27.

Details: ims.nus.edu.sg/events/ma_da...

20.01.2026 02:58 👍 8 🔁 1 💬 0 📌 1
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Quantum Toolbox (15): Relating Relative Entropy and Fidelity (1/6):

15.01.2026 02:04 👍 12 🔁 3 💬 1 📌 1
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Quantum Toolbox (13): Matrix Geometric Mean (1/7)

04.12.2025 07:02 👍 11 🔁 3 💬 1 📌 1
The cover of the first issue of the magazine, "Polynomial Times" (2025-26)

Featured articles:
- Watermarks and Pseudorandom Codes
- Edge Coloring in Nearly Linear Time
- The Compressed Oracle Method and Its Generalization
- Optimal List Decoding

The cover of the first issue of the magazine, "Polynomial Times" (2025-26) Featured articles: - Watermarks and Pseudorandom Codes - Edge Coloring in Nearly Linear Time - The Compressed Oracle Method and Its Generalization - Optimal List Decoding

This new magazine by the @simonsinstitute.bsky.social looks really cool! And great name, too. It was the best of times. Also the worst-case of times.

View online: simons.berkeley.edu/media/28058/...

25.11.2025 23:46 👍 32 🔁 4 💬 1 📌 0

It was a pleasure to work with the team at Futurum to develop these resources on #privacy — I hope you find them interesting (and enjoy the activity sheet puzzle 🧩!)

futurumcareers.com/make-some-no... @futurumcareers.bsky.social

14.11.2025 06:35 👍 5 🔁 3 💬 0 📌 0
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Quantum Toolbox (12): Bretagnolle-Huber Inequality (1/6)

05.11.2025 00:41 👍 12 🔁 2 💬 1 📌 1

Congratulations!! 🎉

28.10.2025 01:16 👍 1 🔁 0 💬 1 📌 0
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Quantum Toolbox (11): Generalized Operator Schwarz Inequality (1/6)

16.10.2025 01:49 👍 5 🔁 2 💬 1 📌 1
A short proof: here is the LaTeX code.

**Proof.** We have, for any $\color{blue}{\lambda} \in\mathbb{R}$,
\begin{align*}
\mathbb{E}[(X-\color{blue}{\lambda})^2]
&= \mathbb{E}[(X-\color{red}{\mathbb{E}[X]} + \color{red}{\mathbb{E}[X]} - \color{blue} {\lambda})^2] \\
&=\mathbb{E}[(X-\color{red}{\mathbb{E}[X]})^2 + 2(X-\color{red}{\mathbb{E}[X]})(\color{red}{\mathbb{E}[X]} - \color{blue} {\lambda}) + (\color{red}{\mathbb{E}[X]} - \color{blue} {\lambda})^2]\\
&=\underbrace{\mathbb{E}[(X-\color{red}{\mathbb{E}[X]})^2]}_{=\textrm{Var}[X]} + 2\underbrace{\mathbb{E}[X-\color{red}{\mathbb{E}[X]}]}_{=0}(\color{red}{\mathbb{E}[X]} - \color{blue} {\lambda})] + (\color{red}{\mathbb{E}[X]} - \color{blue} {\lambda})^2
\end{align*}
and that's all. (The first step is a trick known as *"hiding zero:"* writing $0=a-a$. 🤷)

A short proof: here is the LaTeX code. **Proof.** We have, for any $\color{blue}{\lambda} \in\mathbb{R}$, \begin{align*} \mathbb{E}[(X-\color{blue}{\lambda})^2] &= \mathbb{E}[(X-\color{red}{\mathbb{E}[X]} + \color{red}{\mathbb{E}[X]} - \color{blue} {\lambda})^2] \\ &=\mathbb{E}[(X-\color{red}{\mathbb{E}[X]})^2 + 2(X-\color{red}{\mathbb{E}[X]})(\color{red}{\mathbb{E}[X]} - \color{blue} {\lambda}) + (\color{red}{\mathbb{E}[X]} - \color{blue} {\lambda})^2]\\ &=\underbrace{\mathbb{E}[(X-\color{red}{\mathbb{E}[X]})^2]}_{=\textrm{Var}[X]} + 2\underbrace{\mathbb{E}[X-\color{red}{\mathbb{E}[X]}]}_{=0}(\color{red}{\mathbb{E}[X]} - \color{blue} {\lambda})] + (\color{red}{\mathbb{E}[X]} - \color{blue} {\lambda})^2 \end{align*} and that's all. (The first step is a trick known as *"hiding zero:"* writing $0=a-a$. 🤷)

Here's a classic (but fun to show) fact: if X is any random variable (with a finite variance) and λ is a real, then

𝔼[(X-λ)²] = Var[X]+(𝔼[X]-λ)²

(In particular, this shows that 𝔼[X] is the quantity minimizing 𝔼[(X-λ)²] over all λ, and that Var[X] is the resulting value.)

11.10.2025 04:04 👍 28 🔁 2 💬 2 📌 1
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Quantum Toolbox (10): Uhlmann's Theorem (1/6)

29.09.2025 02:02 👍 10 🔁 3 💬 1 📌 1

Oh, and guess what — not only is this pre #FOCS2025 satellite event free, there is some financial support (covering accommodation, on the #USyd campus) for students available!

Register to the event, apply for travel support! (The latter by Sep 19)
sites.google.com/view/celebra...

13.09.2025 14:01 👍 7 🔁 4 💬 0 📌 0
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Quantum Toolbox (9): Sample Complexity Lower Bounds via Mutual Information (1/6)

10.09.2025 11:03 👍 9 🔁 3 💬 1 📌 1
Post image Post image Post image Post image

🍾💐 Celebrating a successful thesis defence by Josep Lumbreras Zarapico!! 🍉🧀🍪 Advised by @marcotomamichel.bsky.social, Josep defended his thesis "Bandits Roaming Hilbert Space". He will next join Mile Gu’s group as a research fellow. Congrats and all the best, Dr Josep!

12.08.2025 11:56 👍 11 🔁 3 💬 0 📌 0
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Quantum Toolbox (8): Hadamard's Three-Lines Theorem (1/6)

01.08.2025 10:35 👍 11 🔁 4 💬 1 📌 1
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New podcast episode of "Probably Approximately Correct Learners," featuring guest Clément Canonne @ccanonne.github.io!

Check it out on Youtube, Spotify, Apple Podcasts, or wherever you get your podcasts. Subscribe so you don't miss out! (links in the next post) 1/2

10.07.2025 16:26 👍 23 🔁 5 💬 1 📌 0
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Quantum Toolbox (7): Continuity of the von Neumann Entropy (1/6)

05.07.2025 07:22 👍 12 🔁 3 💬 1 📌 1
Preview
Testing (Conditional) Mutual Information We investigate the sample complexity of mutual information and conditional mutual information testing. For conditional mutual information testing, given access to independent samples of a triple of ra...

We are happy to share our work in classical distribution testing "Testing (Conditional) Mutual Information" (arxiv.org/abs/2506.03894), which was recently accepted at COLT 2025. (1/6)

13.06.2025 13:04 👍 9 🔁 3 💬 1 📌 0
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Quantum Toolbox (6): Hoeffding's Inequality (1/7)

11.06.2025 06:57 👍 10 🔁 3 💬 1 📌 1
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Quantum Toolbox (5): Cauchy-Schwarz Inequality (1/6)

06.06.2025 08:15 👍 8 🔁 3 💬 1 📌 1

Quantum state-agnostic work extraction (almost) without dissipation:

We are excited to share a new application of the multi-armed quantum bandit framework—this time in quantum thermodynamics!

21.05.2025 11:46 👍 6 🔁 2 💬 1 📌 0

3. Data-Processing Inequality: bsky.app/profile/qit-...

09.05.2025 02:30 👍 1 🔁 1 💬 0 📌 0
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Quantum Toolbox (2): Schur-Weyl Duality (1/6)

04.05.2025 12:22 👍 13 🔁 3 💬 1 📌 1
Preview
Tips on How to Connect at Academic Conferences I was a kinda awkward teenager. If you are a CS researcher reading this post, then chances are, you were too. How to navigate social situations and make friends is not always intuitive, and has to …

I wrote a post on how to connect with people (i.e., make friends) at CS conferences. These events can be intimidating so here's some suggestions on how to navigate them

I'm late for #ICLR2025 #NAACL2025, but in time for #AISTATS2025 #ICML2025! 1/3
kamathematics.wordpress.com/2025/05/01/t...

01.05.2025 12:57 👍 69 🔁 19 💬 3 📌 2